Some contradiction I can't explain about e^(ix)

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SUMMARY

The discussion centers on the mathematical identity involving Euler's formula, specifically the expression e^{i·2π·k}. It establishes that e^{i·2π·k} equals cos(2πk) + i·sin(2πk), which represents a complex number on the unit circle. The confusion arises from the equivalence e^{i·2π·k} = (e^{i2π})^k = 1^k = 1, leading to the conclusion that all points on the unit circle are equivalent to 1 for integer values of k. The resolution highlights that 1^k in the context of complex numbers refers to all k^{-1} roots of unity.

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Let k be a real number (not necessarily an integer).
[tex]e^{i\cdot2\pi\cdot k}=\cos(2\pi k) + i\sin(2\pi k)=[/tex] some complex number on the unit circe.
BUT
[tex]e^{i\cdot2\pi\cdot k}=(e^{i2\pi})^k=1^k=1[/tex]

so if take [itex]\tilde{k}=2\pi k[/itex] then [itex]1=e^{i\tilde{k}}=[/itex]every other number on the unit circle.

How can this be explained??
Thanks.
 
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solved... I'm an idiot.
[tex]1^k[/tex] with complex numbers are all the unit's [tex]k^{-1}[/tex] roots...
 

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