- #36

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In (6) the LHS is decreasing as ##-k^2## ...haruspex said:It does. It might help to focus by calling the terms on the left of the inequalities just "LHS", as an opaque package.

As k increases, what does (6) tell you is happening to the LHS? Compare that with what happens as k increases in (5).

... but ... when k increases in (5) the LHS decreases (decreases because it's negative) at the lesser rate of k ... ( ! ignoring for the moment that the LHS contains ##k^2## terms )

EDIT I should be talking about the upper bound on the LHS ...

Peter