Some Questions about Papa Rudin (RCA) Chapter 1

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SUMMARY

The discussion focuses on two key questions regarding the proofs in Chapter 1 of Papa Rudin's "Real and Complex Analysis." The first question addresses the measurability of the set E in the proof of Theorem 1.9e, where it is established that |f| is real measurable and that X\E can be expressed as |f|-1((0,∞)). The second question pertains to the Borel nature of the functions φn in the proof of Theorem 1.17, clarifying that φn is a Borel mapping due to the topology generated by open intervals and specific interval forms in [0,∞].

PREREQUISITES
  • Understanding of real measurable functions
  • Familiarity with Borel functions and mappings
  • Knowledge of topological spaces, specifically [0,∞]
  • Proficiency in the concepts presented in Rudin's "Real and Complex Analysis"
NEXT STEPS
  • Study the proofs of Theorem 1.9e and Theorem 1.17 in Papa Rudin's "Real and Complex Analysis"
  • Learn about the properties of Borel sets and Borel functions
  • Explore the topology of [0,∞] and its implications in analysis
  • Review the definitions and properties of measurable functions in real analysis
USEFUL FOR

Students and scholars of real analysis, particularly those studying measure theory and Borel functions, as well as anyone seeking a deeper understanding of the concepts presented in Rudin's work.

joseph.hu37
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Hi dear friends over the Internet,

I have some questions on Papa Rudin:

Question 1:

On page 12 (proof of Theorem 1.9e), why is it that E is measurable?

Question 2:

On page the bottom of page 15 (the proof of Theorem 1.17), why are the φn's Borel functions? Also, the proposition states that f is a measurable function from X to [0,∞ ], but doesn't the definition (at least given in Def 1.3 on p8) require [0, ∞] being a topological space? Then what would be the topology of [0, ∞]?

Thanks, any help is greatly appreciated.
 
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joseph.hu37 said:
Question 1:

On page 12 (proof of Theorem 1.9e), why is it that E is measurable?

Notice that |f| is real measurable and that X\E=|f|-1((0,∞)).

Question 2:

On page the bottom of page 15 (the proof of Theorem 1.17), why are the φn's Borel functions? Also, the proposition states that f is a measurable function from X to [0,∞ ], but doesn't the definition (at least given in Def 1.3 on p8) require [0, ∞] being a topological space? Then what would be the topology of [0, ∞]?

The topology is generated by the open intervals and intervals of the forms [0,b) and (a,∞]. To prove that φn is a Borel mapping, let U be an open set in [0,∞]. If kδn∈U, then [kδn,(k+1)δn)⊂φn-1(U). If n∈U, then [n,∞]⊂φn-1(U). It follows from this that φn-1(U) is a union of Borel sets and therefore φn is a Borel mapping.
 
Hi jgens, thanks for your answer. You are absolutely amazing! Thanks.
 

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