Sound (harmonic) waves questions

Click For Summary

Homework Help Overview

The discussion revolves around harmonic sound waves, specifically focusing on the mathematical representation of pressure waves in a medium. The original poster presents a problem involving the calculation of instantaneous pressure at a given distance and time, using the wave equation P(x,t) = Asin(wt - kx) with specified parameters.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to calculate the instantaneous pressure using the wave equation and provides their reasoning for the values of angular frequency and wave number. Some participants question the assumption of the wave speed in the medium, suggesting that more information is needed to justify the calculations.
  • There is a discussion about the interpretation of the negative pressure result, with participants exploring the implications of this value in the context of atmospheric pressure and sinusoidal variations.

Discussion Status

Participants are actively engaging with the original poster's calculations and assumptions. Some guidance has been offered regarding the interpretation of the negative result, and there is an ongoing exploration of the implications of the sinusoidal nature of the pressure wave.

Contextual Notes

There is mention of specific values such as the speed of sound in air at 343 m/s, which is referenced by the original poster as a basis for their calculations. The discussion also highlights the need for clarity regarding the interpretation of pressure variations in the context of sound waves.

wislagrew
Messages
5
Reaction score
0
Hello,
I have two question regrading sound waves.
The first one:
The pressure P(x;t) at a point x at time t in a medium through which a harmonic wave is
travelling can be described by:
P(x,t) = Asin(wt -kx)
If the equation describes a pressure wave traveling in air, with amplitude 2 Pa and frequency 100 Hz,
find the instantaneous pressure at a distance 10 cm from the source at time 5s.
My solution(am I doing right?):
w=2pi*f
w=2pi*100Hz = 200pi rad/sec;

k=2pi/λ; v=f*λ; λ=343m/s /100 Hz = 3.43m and k=2pi/3.43 =1.83 rad/m;

Finally I have this:
P(x=0.1 ,t=5) = 2sin(200pi*5 -1.18*0.1) = -0.34.

The second question is here
ORWfejn.png

Hope you can help me to figure out the solutions.
Thanks
 
Physics news on Phys.org
wislagrew said:
The first one:
The pressure P(x;t) at a point x at time t in a medium through which a harmonic wave is
travelling can be described by:
P(x,t) = Asin(wt -kx)
If the equation describes a pressure wave traveling in air, with amplitude 2 Pa and frequency 100 Hz,
find the instantaneous pressure at a distance 10 cm from the source at time 5s.
My solution(am I doing right?):
w=2pi*f
w=2pi*100Hz = 200pi rad/sec;

k=2pi/λ; v=f*λ; λ=343m/s /100 Hz = 3.43m and k=2pi/3.43 =1.83 rad/m;
I can see how you approached this, but the assumption of v = 343 m/sec seems unreasonable in light of knowing nothing more than it is sound in "a medium". I think the best you can do is state " I can't see how this can be solved without knowing v or λ so to allow computations I am going to imagine the medium is air at 25C " or something like that.

For your second problem, you'll need to use trig identities, cos (A) + cos (B)
 
Thanks for you reply,
In the end of question's paper it says 343m/sec, so I decided to use it. I'm just confused with the negative result.
 
A sinusoid "with amplitude of 2 Pa" is a convention or standard expression implying pressure varies cyclically from 2 Pa below ambient (rarefaction) to 2 Pa above ambient (compression). If it were intended to be otherwise, the question would be worded to make that clear.
 
So the negative result translates into;
Atmospheric(Pa) + (-0.34 Pa) = Absolute (Pa) ?
 
mic* said:
So the negative result translates into;
Atmospheric(Pa) + (-0.34 Pa) = Absolute (Pa) ?
I assume that's how it is. There is an incremental change in pressure given by that sinusoid.
 
  • Like
Likes   Reactions: 1 person

Similar threads

  • · Replies 2 ·
Replies
2
Views
4K
  • · Replies 1 ·
Replies
1
Views
4K
Replies
5
Views
3K
  • · Replies 6 ·
Replies
6
Views
2K
Replies
7
Views
5K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 27 ·
Replies
27
Views
5K
  • · Replies 8 ·
Replies
8
Views
4K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K