Spacetime diagram problem (spacelike intervals)

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SUMMARY

The discussion centers on calculating the relative speed of a frame in which two spacelike-separated events occur simultaneously on a spacetime diagram. The events are located at coordinates (x=-4, t=5) and (x=0, t=6). The correct relative speed, denoted as Beta, is determined using the formula Beta = Delta(t) / Delta(x), resulting in a value of 0.25. This indicates that the time interval divided by the spatial interval yields the relative speed, which is a fundamental concept in special relativity.

PREREQUISITES
  • Understanding of spacetime diagrams
  • Familiarity with spacelike intervals in special relativity
  • Knowledge of the concept of simultaneity in different reference frames
  • Basic grasp of the formula Beta = Delta(t) / Delta(x)
NEXT STEPS
  • Study the implications of spacelike intervals in special relativity
  • Learn about the Lorentz transformation and its application to simultaneity
  • Explore the concept of world lines and their significance in spacetime diagrams
  • Investigate the relationship between velocity and spacetime intervals in different frames
USEFUL FOR

Students of physics, particularly those studying special relativity, as well as educators and anyone interested in understanding the mathematical relationships in spacetime diagrams.

Moataz
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Homework Statement


Suppose on a spacetime diagram, an event happens at x=-4, t=5 and another event happens at x=0 and t=6. If there is a frame such that the two events happen simultaneously, what would the relative speed of that frame be?


Homework Equations





The Attempt at a Solution



I know this interval is spacelike ( between the two events) but the answer says Relative speed=Beta=Delta(t)/Delta(x)=0.25 But I do not understand why is the speed=time over distance here?
 
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In a spacetime diagram, a point is an event. If a line connects two points, or two events, the line is called the line of simultaneity. The slope of the line of simultaneity is the inverse of the slope of the world line of a moving frame. Therefore, you can find the slope of the line of simultaneity from the two point you are given and then find the slope of the world line.
 
Moataz said:

Homework Statement


Suppose on a spacetime diagram, an event happens at x=-4, t=5 and another event happens at x=0 and t=6. If there is a frame such that the two events happen simultaneously, what would the relative speed of that frame be?

Homework Equations


The Attempt at a Solution



I know this interval is spacelike ( between the two events) but the answer says Relative speed=Beta=Delta(t)/Delta(x)=0.25 But I do not understand why is the speed=time over distance here?
I agree with you. The relative speed should be 4.

Chet
 

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