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Worldlines and spacetime diagrams

  1. Oct 5, 2016 #1
    1. The problem statement, all variables and given/known data
    An observer on the bridge of a spaceship is undergoing a proper acceleration a, so that the
    observer’s worldline expressed in terms of the coordinates of an inertial reference frame S
    is given by
    [tex]t(\tau)=(c/a)\sinh(a\tau/c)[/tex][tex]x(\tau)=(c^2/a)\sinh(a\tau/c)[/tex]
    (a) Draw on a spacetime diagram for the reference frame S the worldline of the observer
    for tau > 0.
    At the instant tau = 0 a radio beacon is dropped off by the observer. At the instant of being
    dropped off, the beacon is at rest relative to the observer. At this instant the beacon also
    starts emitting at regular intervals (according to a clock on the beacon) a series of very short
    pulses towards the observer.
    Consider the signal pulse emitted at a time tE in the reference frame S.

    (b) Draw on the spacetime diagram of part (a) the worldline of the beacon. Hence show
    that this emission event has the spacetime cordinates [tex] (ct_E,x_E)=(ct_E,c^2/a)[/tex]
    (c) Show that the spacetime displacement of this emission event with respect to the origin
    of S is given by the four vector
    [tex]
    \textbf{s}_E=ct_E\textbf{e}_0+(c^2/a)\textbf{e}_1
    [/tex]
    (d) Draw on the spacetime diagram the world line of the pulse emitted at time tE:

    2. Relevant equations
    [tex]
    (\cosh(x))^2-(\sinh(x))^2=1
    [/tex]

    A four vector is defined as:
    [tex]
    \textbf{s}=\Delta ct\textbf{e}_0+\Delta x\textbf{e}_1+\Delta y\textbf{e}_2+\Delta z\textbf{e}_3
    [/tex]

    3. The attempt at a solution
    (a)
    Rearranging the given equations:
    [tex]\sinh(a\tau/c)=at/c[/tex][tex]\cosh(a\tau/c)=ax/c^2[/tex]
    Substituting into the relation between sinh and cosh:
    [tex](ax/c^2)^2-(at/c)^2=1[/tex][tex](a^2x^2-a^2c^2t^2)/c^4=1[/tex][tex]x^2=c^2t^2+c^4/a^2[/tex] (1)

    (b)
    when tau=0:
    [tex]t(0)=0[/tex][tex]x(0)=c^2/a[/tex]
    this part I'm not so sure of, but here is what I did:
    using the equation of motion [tex]x_f=x_i+ut+(1/2)at^2[/tex][tex]x = -½ac^2t^2 + c^2/a[/tex]
    rearranging:
    [tex]ct=\sqrt{(c^2/a-x)/(a/2)}[/tex] (2)

    I'm not quite sure of my solutions for (a) and (b). Assuming I have the correct equations (1) and (2), all that remains is to plot them on the same plot of ct vs x?

    (c)
    substituting the spacetime coordinates [tex](ct_E,c^2/a)[/tex] into the definition of a four-vector:
    [tex]
    \textbf{s}_E=(ct_E-0)\textbf{e}_0+(c^2/a-0)\textbf{e}_1+(0-0)\textbf{e}_2+(0-0)\textbf{e}_3=ct_E\textbf{e}_0+c^2/a\textbf{e}_1
    [/tex]

    (d)
    For this part I'm assuming that I have to draw a straight line of slope 1 or -1, intersecting the wordline of the beacon at an arbitrary time coordinate t_E, such that it also intersects the wordline of the observer. Is this correct?

    Any help would be appreciated :)
     
  2. jcsd
  3. Oct 5, 2016 #2

    vela

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    This is fine.

    First, why do you expect the beacon to accelerate once it's released from the ship, because that's what you're assuming here? Second, what's ##u##? Did you set it to 0? Third, are you sure the Newtonian kinematic equations are valid here? After all, this is a special relativity problem.

    I'd start by finding the velocity of the beacon when it's released.

    Yes.

    The slope will be ##\pm 1##, but the line may or may not intersect with the world line of the observer.
     
  4. Oct 6, 2016 #3
    Thanks for your reply :)

    Here is what I have come up with for part (b):
    I have already worked out the coordinates for the release of the beacon as (x,ct)=(c^2/a,0). So the worldline of the beacon intersects that of the ship at that point. Now, as you pointed out, the beacon would not necessarily accelerate upon release. So, would it be a straight line that is tangent to the point of release on the ship's wordline? My reasoning for this is that since it is at rest relative to the ship at that instant, their velocities would be equal at that point when plotted on the spacetime diagram.

    I'm fairly sure that my part (c) is correct. Could you confirm this?
     
  5. Oct 6, 2016 #4

    vela

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    Sounds good.

    Looks good too.
     
  6. Oct 10, 2016 #5
    For the spacetime diagram in Q1, I got a wordline for the beacon as a straight vertical line, intersecting that of ship at x=c^2/a. I'm not quite sure about this.

    Problem statement
    Q1
    (e) The pulse is received by the observer at the observer’s proper time R. Show that this
    event can be represented, with respect to the origin of S, by the position four vector
    [tex]
    s_R=(c^2/a)(\sinh{(a\tau_R/c)}\textbf{e}_0+\cosh{(a\tau_R/c)}\textbf{e}_1)
    [/tex]

    (f) The world line of the pulse (consisting of zero-rest mass particles) can then be parameterised
    in terms of the affine parameter as
    [tex]
    s(\lambda)=s_E (1-\lambda)+s_R\lambda
    [/tex]
    Write down the four-velocity u of this pulse.

    (g) Using the fact that u is a null vector, show that u0 = u1.

    (h) Using the result of part (g), show that the time of reception of the pulse will be given
    by:
    [tex]
    \tau_R=-(c/a)\ln{(1-at_E/c)}
    [/tex]

    Attempt at a solution
    Q1
    (e)
    I had no issues with this part.

    (f)
    subbing in s_E and s_R and evaluating, assuming my algebra is correct:
    [tex]
    s(\lambda)=(ct_E(1-\lambda)+\lambda(c^2/a)\sinh{(a\tau_R/c)})\textbf{e}_0+((c^2/a)(1-\lambda)+\lambda(c^2/a)\cosh{(a\tau_R/c)}))\textbf{e}_1
    [/tex]
    then, the four-velocity is, by differentiating:
    [tex]
    \textbf{u}=(\lambda c)(\cosh{(a\tau_R/c)}\textbf{e}_0+\sinh{(a\tau_R/c)}\textbf{e}_1)
    [/tex]

    (g)
    for a null vector the absolute value should be 0:
    [tex]
    \sqrt{(u_0)^2+(u_1)^2}=0
    [/tex]
    [tex]
    \pm((u_0)^2+(u_1)^2)=0
    [/tex]

    (h) I am not sure how to use the result of part (g) when solving for tau_R. Is the idea to substitute this into the four-vector derived in part (f)?
     
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