There is something about the twin paradox in special relativity that has always bothered me. One twin sets out on a journey at a large fraction of the speed of light, turns around and returns. The fact that the returning twin is the one who is younger is explained by the fact that they are the one who had to accelerate, and then slow down, turn around, and accelerate again. Fine. I’ve never had a problem with that. But what I’ve never seen addressed is the scenario in which both twins, starting at the same place, accelerate in opposite directions at a large fraction of light speed, then turn around and head back at the same high speed and meet where their respective journeys began. Whose time was slower in the completely symmetric scenario?