- #1
dongsh2
- 28
- 0
Do some one know how to integrate the
Hermite(2n+1,x)*Cos (bx) and e^(-x^2/2), x from 0 to infinity?
Hermite(2n+1,x)*Cos (bx) and e^(-x^2/2), x from 0 to infinity?
Svein said:Check out http://en.wikipedia.org/wiki/Gaussian_integral. It tells you most of what you need to know about that integral.
I did not say it was easy, I just gave you an idea of how to attack it.dongsh2 said:However, it is not easy as what you thought.
The formula for Special Integral Hermite(2n+1,x)*Cos (bx) is given by:
∫(Hermiten(x) * cos(bx)) dx = (Hermiten+1(x) * sin(bx)) / b + C
where Hermiten(x) is the Hermite polynomial of degree n.
This special integral is used in various mathematical applications, such as in quantum mechanics, signal processing, and statistical mechanics. It is also used to solve differential equations and in the calculation of probabilities in statistics.
The Special Integral Hermite(2n+1,x)*Cos (bx) is closely related to the Gaussian function e^(-x^2/2). In fact, the Hermite polynomials are orthogonal to the Gaussian function, which makes them useful in various mathematical calculations.
Yes, the Special Integral Hermite(2n+1,x)*Cos (bx) can be evaluated analytically using the formula mentioned in the first question. However, for higher values of n, the integration can become more complex and numerical methods may be used.
Yes, this special integral has many real-life applications. It is used in the calculation of wave functions in quantum mechanics, in the analysis of signals in signal processing, and in the calculation of probabilities in statistics. It is also used in modeling various physical phenomena in engineering and physics.