Special relativity:2 ships pass eachother

  • Thread starter Thread starter bfusco
  • Start date Start date
  • Tags Tags
    Ships
Click For Summary
SUMMARY

This discussion focuses on calculating the relative speed of two spaceships, A and B, using Lorentz transformations in the context of special relativity. Ship A is 90 meters long, and ship B is 200 meters long. The observer on ship A measures the time it takes for the tip of ship B to pass as 5 x 10-7 seconds. The solution involves determining the apparent velocity using the formula u' = (u - v) / (1 - vx/c2) and applying Lorentz transformations to find the time observed by a person on ship B.

PREREQUISITES
  • Understanding of Lorentz transformations in special relativity
  • Familiarity with reference frames in physics
  • Basic knowledge of velocity calculations
  • Ability to manipulate algebraic equations
NEXT STEPS
  • Study the derivation and application of Lorentz transformations in detail
  • Learn how to calculate relative velocity in different reference frames
  • Explore the concept of time dilation and length contraction in special relativity
  • Practice solving problems involving relative motion and reference frames
USEFUL FOR

Students of physics, particularly those studying special relativity, educators teaching relativity concepts, and anyone interested in understanding the implications of relative motion in different reference frames.

bfusco
Messages
126
Reaction score
1

Homework Statement


Two space ships A (90m long) and B (200m long) travel towards each other. The person in ship A observes that it takes 5x10-7s for the tip of ship B to pass his ship. What’s the relative speed of the two ships? How long does a person sitting at the tip of ship B observe for his ship to pass ship A?

The Attempt at a Solution


at the moment in class we are on the topic of Lorentz transformations. so i am going to assume that this problem is to be done in that way.

i am having a hard time in general setting up any equations to these word problems as this new idea of reference frames is confusing me in terms of writing the equations.

so what i got so far is this (with help from my textbook, not really from any understanding of my own): i am going to start by indicating that spaceship A will be the fixed system K, and spaceship B be will be the moving system K'. since i am given Δt i figure that i would have to solve for the apparent velocity of the system u'. u'=dx'/dt', using the lorentz transformation i plug in dρ(x-vt)/dρ(t-vx/c^2) ρ=1/sq.rt.(q-(v/c)^2) and after some algebra i get u'=u-v/1-vx/c^2).

the time it takes for person sitting at the tip of ship B observe his ship to pass ship A I am going to call Δt'=t2'-t1'. using the lorentz transformation i get ρ(t2-vx2/c^2)-ρ(t1-vx1/c^2) and after some algebra i got ρ[(t2-t1) - (v/c^2)(x2-x1)]. t2-t1=Δt=5 x 10^-7s and x2-x1=90m (i think), and i would think i answered the question, but as i said before i kinda just got it from the textbook if someone could help explain some of this to me.
 
Physics news on Phys.org
To solve the first part, you don't need relativity. You know that in A's reference frame a particular point on B takes a given time to travel a given distance. From that it is trivial to find B's velocity in A's frame.

For the second part, you do need relativity. Use the velocity calculated above, find the length of A in B's frame, and find the time from that.
 
The first part boils down to the following question: If you are at rest in the K frame of reference, how do you measure the relative velocity of the K' frame of reference relative to your own frame of reference if the only measurement tools available to you are meter sticks and synchronized clocks? Well you focus on a specific point x'=constant in the K' frame of reference, and record the time t that this material point passes various locations x in your frame of reference. You then plot a graph of x versus t, and fit a straight line to the data. The relative velocity is slope of this line. That is,
v=(\frac{\Delta x}{\Delta t})_{x'=const.}
Or, in terms of the symbology of partial derivatives,v=(\frac{\partial x}{\partial t})_{x'}
In the case of your problem, the point you are focusing upon is the tip of ship B, and you are measuring the time interval between when the tip is at x = 0 and x = 90 m.

Chet
 

Similar threads

  • · Replies 10 ·
Replies
10
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 17 ·
Replies
17
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 4 ·
Replies
4
Views
1K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 3 ·
Replies
3
Views
3K