Special relativity and velocity of a particle

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In a high-energy accelerator experiment, two particles approach each other at speeds of f times the speed of light. To find the relative velocity of one particle to the other, the Lorentz velocity transformation equation is applied. The calculation shows that the relative velocity is f^2 times the speed of light, which seems to exceed the speed limit set by special relativity. However, this outcome highlights the principles of special relativity, emphasizing that while individual speeds can appear greater than light, their relative speed remains constrained. The discussion underscores the complexity of velocity transformations in relativistic contexts.
matpo39
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hi, I am having a little trouble figuring this problem out.

Two particles in a high-energy accelerator experiment are approaching each other head-on. Each has a speed which is f times the speed of light, as measured in the laboratory. What is the magnitude of the velocity of one particle relative to the other? Give your answer as a fraction of the speed of light.

I believe that you will have to use the lorentz velocity transformation equation which is v_1= v_2+u/(1+u*v_2/c^2) . but the answer doesn't involve u so I am not sure where to go with this problem.

thanks
 
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matpo39 said:
hi, I am having a little trouble figuring this problem out.

Two particles in a high-energy accelerator experiment are approaching each other head-on. Each has a speed which is f times the speed of light, as measured in the laboratory. What is the magnitude of the velocity of one particle relative to the other? Give your answer as a fraction of the speed of light.

I believe that you will have to use the lorentz velocity transformation equation which is v_1= v_2+u/(1+u*v_2/c^2) . but the answer doesn't involve u so I am not sure where to go with this problem.
The velocity of the one particle relative to the other is:

u = \frac{v_1 - v_2}{1 - v_1v_2/c^2}

Where v_2 = - v_1 = fc, you get:

u = 2fc/ (1 + f^2)

AM
 
for any help

Based on the information given, it seems that both particles have a speed of f times the speed of light, so we can assume that u (the relative velocity between the two particles) is also f times the speed of light. Using the Lorentz velocity transformation equation, we can find the magnitude of the velocity of one particle relative to the other:

v_1 = v_2 + u/(1+u*v_2/c^2)

Since both particles have the same speed, v_2 is also f times the speed of light. Plugging in the values, we get:

v_1 = f*c + f*c/(1+f^2*c^2/c^2)

Simplifying and solving for v_1, we get:

v_1 = f^2*c/(1+f^2)

Therefore, the magnitude of the velocity of one particle relative to the other is f^2 times the speed of light, which is still greater than the speed of light. This is a result of special relativity, which states that the speed of light is the maximum speed at which any object can travel. So even though the particles have a speed greater than the speed of light, their relative velocity is still limited by the speed of light. I hope this helps clarify the problem for you.
 
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