uons are unstable subatomic particles that decay to electrons with a mean lifetime of 2.2 microseconds. They are produced when cosmic rays bombard the upper atmosphere about 12.3km above the earth's surface, and they travel very close to the speed of light. It is known that these muons reach the ground. From the point of view of the muon, it still lives for only 2.2 microseconds, so how does it make it to the ground? What is the thickness of the 12.3 km of atmosphere through which the muon must travel, as measured by the muon? Assume speed of muon is .999c
time dilation, length contraction
The Attempt at a Solution
I am not so much asking for a solution as I am asking why what I have done is wrong.
The scenario is that the muon is flying towards earth at a really high speed, and we are given its lifetime in respect to the muon's frame of reference.
So to me it makes sense to think of the following: That the muon is at rest and that the atmosphere and the earth are moving with the same speed towards the muon that the muon was moving towards the earth in the previous frame of reference.
By doing this and assuming that the muon does actually hit the earth, it follows logically (in my head) that because we have the velocity of the earth in respect to the muon's reference frame, and that we have the lifetime of the muon in respect to the muon's reference frame, that we can solve for the height of the atmosphere in respect to the muon's reference frame.
d=660m = 0.66km
Please, if you can, point out the error in what I've done or tell me if you agree with my result.