Special relativity, time dilation and rockets

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SUMMARY

The discussion centers on the calculation of time intervals in the context of special relativity, specifically focusing on time dilation experienced by a rocket traveling at 60% the speed of light (v = 3/5c). The calculated time interval in the Earth’s rest frame (Δte) is 5.56 x 10-7 seconds, while the time interval measured on the rocket's clock (Δtr) is 6.94 x 10-7 seconds. The equations used include Δte = d/v and Δtr = 1/sqrt(1-(v/c)2)Δte, confirming the application of time dilation principles accurately.

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  • Understanding of special relativity concepts
  • Familiarity with time dilation equations
  • Basic knowledge of the speed of light (c)
  • Ability to perform calculations involving square roots and scientific notation
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  • Study the Lorentz transformation equations in special relativity
  • Learn about the implications of time dilation in high-speed travel scenarios
  • Explore the concept of simultaneity in different reference frames
  • Investigate practical applications of special relativity in modern physics
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Students and educators in physics, particularly those studying special relativity, as well as anyone interested in the effects of high-speed travel on time perception.

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Homework Statement



Lights are placed at points A and B, which are 100m apart as measured in the rest frame of the earth. As a rocket moving at speed v = 3/5c, passes point A the light turns on. As the rocket passes point B, the second light turns on.
As read on the rockets clock, the time difference between the events was Δtr. Clocks synchronized in the rest frame of the Earth measure a time interval Δte between the events.

a) Determine Δte.
b) Determine Δtr using time dilation.

Homework Equations



Δte = d/v (where d = 100m)

Δtr = 1/sqrt(1-(v/c)^2)Δte


The Attempt at a Solution



Δte = 5.56 x 10^(-7) s
Δtr = 6.94 x 10^(-7) s

However I'm unsure as to whether I've used the right times for the different values of t.
 
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looks good to me, i got the same answers
 

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