A boat with mast at angle θ to its deck is travelling at velocity v relative to an observer, what angle does this observer see.
The Attempt at a Solution
So by using Lorentz Transformation: x'=(x-vt)*g where g=gamma
The mast is length 'r'' and at an angle θ' to the deck of the moving boat, so x' = r'*cos(θ')
By substitution, r'*cos(θ') = (x-vt)g and θ' = cos-1(x-vt/r'*√(1-(v2/c2))).
Am I right or not? Thanks