Special Theory of Relativity question

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SUMMARY

The discussion focuses on a problem related to the Special Theory of Relativity, specifically involving a clock moving at a velocity of u = 3c/5. The user applies the Lorentz transformation to determine the location of the clock in their frame when it ticks 1 second in its frame, calculating its position as x = 2.25 * 10^8 m. Additionally, the user attempts to find the time t^* when a light pulse emitted from the clock reaches their origin, concluding that t^* equals 2 seconds. The user expresses uncertainty about their initial assumptions and calculations, particularly regarding the application of the Lorentz transformation.

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Homework Statement


A clock moving at velocity u = 3c/5 passes me, sitting at my origin, at t = t' = 0 according to it and my clock. What is its location in my frame when it ticks 1 second in its frame? If it emits alight pulse at that time, at what time t^* according to me will that pulse reach my origin? Use (x, t) for me and (x', t') for clock frame.
I took this form Yale Open Course

Homework Equations


Special Relativity equations


The Attempt at a Solution


I will try to divided this problem into two parts: First one is - what is its location
in my frame when it ticks 1 second in its frame?
and second one - If it emits alight pulse at that time, at what time t^∗ according to me will that pulse reach my origin?.

So for the first one i have x=? and that t'=1. I use the lorentz transformation for x point.
x=(x' + ut')/SQRT(1-(u^2)/(c^2)). I am not sure that i can use this formula for this purpose
but if i assume that x' is 0 i get x= ut'/SQRT(1-(u^2)/(c^2)) = 2.25 * 10^8 m
Then i need to find t when light hits my origin ie t^* = t + t'' where t'' is time light takes to travel to my origin in my frame. Perhaps i can get t buy manipulating lornetz equation for t'. Since i have t' and x i can figure out t. t' = (t - (ux/c^2))/SQRT(1-(u^2)/(c^2)) ==>
1 = (t - (ux/c^2))/0.8 ==> 0.8 + 0.45 = t = 1.25. So then i need to find t''. I have no idea to how to find t'' unless to plug int into standard v=s/t formula. If that's the case then c=x/t ==>
t= 0.75 where x is 2.25 * 10^8 m which i found in first part of the problem. So t^* is 2.

I have a feeling that i made a mistake somewhere, possibly at the beginning of the problem where i assumed that x= ut'/SQRT(1-(u^2)/(c^2)) and i am not sure if that's quite right.
 
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