Specific Gravity Question - Please check my answer

[benworld]

Homework Statement

A stoppered bottle, weights 38.215 g when empty , weights 45.362 g when filled with water. When filled with unknown liquid the bottole and unknown weighs 44.221 g. Calculate the liquid's specific gravity :

Homework Equations

D = m / v

s.g.. = density of unknown / density of water

The Attempt at a Solution

Density of water = 1 g/ml

m = 44.221 g - unknown

v = 44.21 - 38.215 = 6.00 ml

d = m /v

d = 44.221 / 6.00 = 7.362 g/ml unknown

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Fiding density of water

v = 45.362 g - 38.215 g
v = 7.147
d = 45.362 / 7.147 = 6.347 g

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Specific Gravity

= 7.362 g/ml 6.347 g/ml = 1.160 g/ml


is the answer 1.160 g/ml ? Correct or wrong ?

 

[Lok]

Wrong. Answer has to be smaller than 1.000 g/ml.

For some reason you got mililiters when you substracted to weights.