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Specific Gravity Question - Please check my answer

  1. Feb 9, 2010 #1
    1. The problem statement, all variables and given/known data

    A stoppered bottle, weights 38.215 g when empty , weights 45.362 g when filled with water. When filled with unknown liquid the bottole and unknown weighs 44.221 g. Calculate the liquid's specific gravity :


    2. Relevant equations

    D = m / v

    s.g.. = density of unknown / density of water

    3. The attempt at a solution

    Density of water = 1 g/ml

    m = 44.221 g - unknown

    v = 44.21 - 38.215 = 6.00 ml

    d = m /v

    d = 44.221 / 6.00 = 7.362 g/ml unknown

    ---------------
    Fiding density of water

    v = 45.362 g - 38.215 g
    v = 7.147
    d = 45.362 / 7.147 = 6.347 g

    ------------

    Specific Gravity

    = 7.362 g/ml 6.347 g/ml = 1.160 g/ml


    is the answer 1.160 g/ml ? Correct or wrong ?
     
  2. jcsd
  3. Feb 9, 2010 #2

    Lok

    User Avatar

    Wrong. Answer has to be smaller than 1.000 g/ml.

    For some reason you got mililiters when you substracted to weights.
     
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