Density Problem - Please lookover my answer

  • Thread starter Thread starter benworld
  • Start date Start date
  • Tags Tags
    Density
Click For Summary
SUMMARY

The density of an unknown liquid was calculated using the formula D = m / v, where the mass (m) was determined by subtracting the weight of an empty Erlenmeyer flask (48.217 g) from the total weight with the liquid (57.056 g), resulting in 8.839 g. The volume (v) was given as 10.00 mL. The calculated density is 0.8839 g/mL, which should be rounded to 0.884 g/mL based on significant figures, as the volume measurement (10.00 mL) dictates the precision of the final answer.

PREREQUISITES
  • Understanding of density calculation (D = m / v)
  • Knowledge of significant figures in measurements
  • Familiarity with mass and volume measurements
  • Basic proficiency in using laboratory equipment like an Erlenmeyer flask
NEXT STEPS
  • Review significant figures rules in scientific calculations
  • Practice density calculations with varying volumes and masses
  • Explore the implications of precision in scientific measurements
  • Learn about the properties of liquids and their density variations
USEFUL FOR

Students in chemistry courses, educators teaching density concepts, and anyone interested in mastering calculations involving significant figures and density measurements.

benworld
Messages
7
Reaction score
0

Homework Statement



A 10.00 mL volume of unknown liquid was added to stoppered erlemeyer flask, which weighed 48.217 g. If weigh of the unknown liquid plus the stoppered flask was 57.056 g. Calculate density of unknown to correct number of signifigent figure.


Homework Equations



D = m /v


3. The Attempt at a Solution [/b

D = m / v

v = 10.00 ml

m = 57.056 - 48.217 = 8.839 g

d = 8.839 g / 10.00 ml = 0.8839 g/ml

Answer is 0.8839 g/ml

is this correct ? or should I round it to 0.884 g/ml ]
 
Physics news on Phys.org
benworld said:

A 10.00 mL volume of unknown liquid was added to stoppered erlenmeyer flask, which weighed 48.217 g. If weigh of the unknown liquid plus the stoppered flask was 57.056 g. Calculate density of unknown to correct number of signifigent figure.

Seems correct, but what is that about a "signifigent figure"?
 
I actually believe that it would be .88. With sig figs you round to the lowest amount of sig figs found in the given information. In this problem it would be the 10.00 mL, the 0 after the decimal are just place holders, insignificant.

Joe
 

Similar threads

  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
4K
  • · Replies 5 ·
Replies
5
Views
7K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 15 ·
Replies
15
Views
6K
Replies
7
Views
5K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 11 ·
Replies
11
Views
3K