Specific heat capacity and final temperature

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Homework Help Overview

The problem involves calculating the final temperature of a metal and water system, where a metal sample is heated and then placed in water. The specific heat capacities of both substances are relevant to the heat transfer involved.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the heat transfer equation, questioning the setup of the heat loss and gain expressions. There are attempts to clarify the specific heat values and their units, as well as the correct formulation of the temperature changes involved.

Discussion Status

Multiple interpretations of the heat transfer equation are being explored, with participants providing different calculations and questioning each other's reasoning. Some guidance has been offered regarding the correct approach to the temperature changes, but no consensus has been reached on the final temperature.

Contextual Notes

Participants are working under the constraints of homework rules, which may limit the information they can share or the methods they can use. There is an ongoing discussion about significant figures and their impact on the calculations.

moimoi24
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Homework Statement



A 2.8 kg sample of a metal with a specific heat of 0.43KJ/KgC is heated to 100.0C then placed in a 50.0 g sample of water at 30.0C.* What is the final temperature of the metal and the water?


Homework Equations



heat loss by the metal = heat gain by the water

The Attempt at a Solution



I solve it this way:
2800 g x 430 J/gC x (Tf-100) = 50 g x 4.2 J/gC x (Tf - 30)

my final answer is 100 C,

please help me check what makes my answer wrong because the answer on the key is 97C...

Thanks a lot...
 
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i solve it again and i got 114 as the answer because of 0.43KJ/KgC, it will be 0.43J/gC... Please help me with this one, what makes it wrong?
 
moimoi24 said:

Homework Equations



heat loss by the metal = heat gain by the water

The Attempt at a Solution



I solve it this way:
2800 g x 0.430 J/gC x (Tf-100) = 50 g x 4.2 J/gC x (Tf - 30)

Check the red one. Is it really the heat lost by the metal?


ehild
 
ehild said:
Check the red one. Is it really the heat lost by the metal?


ehild

is it 2800 g x 0.43J/gC x 70 C?
 
You said that the heat lost by the metal is equal to the heat gained by water.
The metal cools down from 100 C° to Tf, how much heat releases in the cooling process?

ehild
 
ehild said:
You said that the heat lost by the metal is equal to the heat gained by water.
The metal cools down from 100 C° to Tf, how much heat releases in the cooling process?

ehild
i think it should be100C - tf, since there is a decrease in temperature. my answer is 90C, is that correct?
 
moimoi24 said:
i think it should be100C - tf, since there is a decrease in temperature. my answer is 90C, is that correct?

Yes, you need to calculate with 100-Tf, but I got different result. Do not drop significant digits during the calculations.

ehild
 

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