A 2.8 kg sample of a metal with a specific heat of 0.43KJ/KgC is heated to 100.0C then placed in a 50.0 g sample of water at 30.0C.* What is the final temperature of the metal and the water?
heat loss by the metal = heat gain by the water
The Attempt at a Solution
I solve it this way:
2800 g x 430 J/gC x (Tf-100) = 50 g x 4.2 J/gC x (Tf - 30)
my final answer is 100 C,
please help me check what makes my answer wrong because the answer on the key is 97C...
Thanks a lot....