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## Homework Statement

**mass,**

*m*, of water in kettle1.5 kg

**power rating,**

*P*, of kettle2.1 kW

**time interval,**

*t*, for heating322 seconds

**starting temperature**

4 °C = 277 K

**finishing temperature**

100 °C = 373 K

**temperature change, Δ**

*T*96 K

**electrical energy supplied,**

*E*=*P*×*t*(2.1x10^3)(322) = 6.8x10^5 J

**calculate the specific heat capacity:**

c = q/(m)(delta t)

## Homework Equations

## The Attempt at a Solution

Why do i keep getting the wrong answer?

q = 6.8 x 10^5

m = 1.5kg

t = 322

Thus c = 6.8 x 10^5/1.5*322 = 1407.8674948240165631469979296066252587991718426501035

But im sure that's wrong, it's not supposed to be the exact figure, as this was a rough experiment done at home. It's way off, where am i going wrong? thanks