What Is the Final Temperature When Ice Melts in Water?

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SUMMARY

The final temperature when 0.50 kg of ice at 0°C is added to 1 kg of water at 20°C is calculated using the principles of thermal equilibrium. The specific heat of ice is 2000 J/kg°C, while the specific heat of water is 4186 J/kg°C, and the latent heat of fusion is 33.5 x 104 J/kg. The equation used is Q_gain(ice) = Q_lost(water), leading to a final temperature of approximately 0°C, as the energy required to melt the ice exceeds the energy available from the water before it cools to 0°C.

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Homework Statement



An insulated cup contains 1kg of water initially at 20 C. 0.50 kg of ice, initially at
0 C is added to the cup of water. The water and ice are allowed to come to thermal equilibrium. The specific heat of ice is 2000 J/kg oC, the specific heat of water 4186 J/kg oC, the latent heat of fusion of water is 33.5x104J/kg. What is the final temperature of the water?

(A) 0 C
(B) 1.2 C
(C) 4.6 C
(D) 9.2 C
(E) 15.2 C



Homework Equations


Q_gain(ice) = Q_lost(water)
mc(Ti-Tf) = mLf + mc(Tf-0)


The Attempt at a Solution


Q_gain(ice) = Q_lost(water)
mc(Ti-Tf) = mLf + mc(Tf-0)
(1.0)(4186)(20 - Tf) = (.5)( 33.5x104 ) + (.5)(4186)(Tf)
83,720 – 4186Tf = 167,500 + 2093 Tf
-83780= 6279 Tf
-13.3 = Tf
 
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Correct method
But what is the total energy needed to melt the ice?
How much energy can you get from the initial water before it cools to 0c?
 
Last edited:

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