mugzieee
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A 300-m tall tower is built on the equator. How much faster does a point at the top of the tower move than a point at the bottom?
Speed difference between top and bottom of equatorial tower
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Science Advisor
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{Period of Earth's Rotation} = T = (86400 sec)mugzieee said:
{Radius of Earth} = R
{Tower Bottom Speed} = 2*Pi*R/T
{Tower Top Speed} = 2*Pi*(R + 300 meters)/T
{Tower Top Speed} - {Tower Bottom Speed} = {2*Pi*(R + 300 meters)/T} - {2*Pi*R/T} =
= 2*Pi*(300)/T
= 2*Pi*(300)/(86400)
= (0.02182 m/sec)
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mugzieee
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hey bro how did you get the T=86400 sec? thanks for your help, it was the correct answer!
mugzieee
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sorry, that was a thoughtless question which i realized afterwards. thank you 