Speed from a distance vs. time graph

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ravsterphysics
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Homework Statement


Distance-time graph of a car, distance in cm against time in s from 0.00 to 4.00 s, rising in an S-shape to a plateau near 110 cm, with steepest slope around 1.0 to 1.5 s.


Homework Equations

The Attempt at a Solution


I know velocity = distance/time and the steepest gradient means the maximum speed, and the gradient is steepest between 1 and 1.5 seconds with the change in distance being around 40cm so velocity = 40cm/0.5 = 80 cm per second.

So my answers are nowhere near what they want.

Where am I going wrong?
 
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  • Distance-time graph of a car: distance in cm from 0 to 120 against time in s from 0.00 to 4.00. The curve rises steeply around 1.0 to 1.5 s, then flattens toward about 110 cm.
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You want an estimate of the maximum instantaneous speed. You might need to "zoom in" to a much smaller interval of time where the graph is steepest.
 
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