Speed of a Rocket far from Earth

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SUMMARY

The discussion centers on calculating the speed of a rocket launched from Earth's surface at 1.60×104 m/s when it is very far from Earth. The relevant equations include gravitational force, potential energy, and kinetic energy, with escape velocity established at 11200 m/s. The initial approach of subtracting the rocket's speed from the escape velocity was incorrect. The correct method involves applying the conservation of energy principle, which was clarified through community assistance.

PREREQUISITES
  • Understanding of gravitational force and its formula: F = (GMm)/r2
  • Knowledge of potential energy and kinetic energy equations
  • Familiarity with the concept of escape velocity
  • Basic principles of conservation of energy
NEXT STEPS
  • Study the derivation of escape velocity and its implications in rocketry
  • Explore conservation of energy in gravitational fields
  • Learn about the effects of altitude on gravitational force
  • Investigate real-world applications of rocket propulsion and energy conservation
USEFUL FOR

Students in physics, aerospace engineering enthusiasts, and anyone interested in the principles of rocketry and energy conservation in gravitational fields.

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Homework Statement



A rocket is launched straight up from the Earth's surface at a speed of 1.60×10^4 m/s.
What is its speed when it is very far away from the earth?

Homework Equations


F= (GMm)/r^2
G= 6.67 X 10^-11
M= 5.98 X 10^24

Potential Energy = (Gm1m2)/r
Kinetic Energy = 1/2mv^2
Escape velocity= 11200 m/s

The Attempt at a Solution



My first attempt was to take the speed of the rocket (1.60 X 10^4) and subtract it from the escape velocity. This gave me 4800 m/s. This assignment is online and the program said that answer is incorrect. Now I am not sure how to approach the problem. Does anyone have advice as to how to start this problem? All help is greatly appreciated. Thank you.
 
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Try using conservation of energy.
 
Conservation of energy was my second attempt. I set it up as this:

P.E. + K.E. = K.E. + P.E.


OH! I see. Dang, for some odd reason the first time I tried this approach I used 9.8 as the value for P.E. ...how foolish. I see now. Thank you so much. Man, I cannot afford to do that on a test. Thanks again.
 

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