Speed of a Satellite at 320 kn: Calculate Time Period

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SUMMARY

The discussion centers on calculating the speed of a satellite at a height of 320 kilometers with a time period of 90 minutes. The formula S = d/t is relevant, where 'd' represents the distance traveled in one complete orbit around the Earth. The time period refers to the duration it takes for the satellite to complete one full revolution around the Earth, which is confirmed by participants in the discussion.

PREREQUISITES
  • Understanding of orbital mechanics
  • Familiarity with the formula S = d/t
  • Knowledge of Earth's radius (approximately 6,371 kilometers)
  • Basic concepts of satellite motion and time periods
NEXT STEPS
  • Calculate the orbital speed of satellites using the formula v = 2πr/T
  • Research the effects of altitude on satellite speed and time period
  • Explore gravitational forces acting on satellites in orbit
  • Learn about different types of satellite orbits and their characteristics
USEFUL FOR

Aerospace engineers, physics students, and anyone interested in satellite dynamics and orbital calculations will benefit from this discussion.

MoniMini
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Hi !
"What is the speed of a satellite which is at a height of 320 kn and has a time period of 90 minutes"

I've never come across such a question ever before.
Is there any formula to solve this problem? or do we have to use S= [itex]d/t[/itex]
And what exactly does "time period" mean here? The time taken by the satellite to revolve around the Earth once?, or something else?

Thanks!
~MoniMini
 
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This sounds a bit like homework but it's an easy problem as long as you remember to include the radius of the Earth when you calculate the distance the whole way round!
And, yes, that's what they mean by "time period"
 

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