Speed of a transverse wave along a wire?

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SUMMARY

The speed of a transverse wave along a steel wire can be calculated using the formula v = √(FL/mass), where F is the force of tension, L is the length of the wire, and mass refers to the mass of the wire itself. In this discussion, a 2 kg mass is used to create tension, but the mass of the wire is critical for accurate calculations. Participants emphasize that neglecting the mass of the wire is incorrect, and the density of steel must be referenced to determine the wire's mass. The consensus is to seek clarification from the instructor regarding the expectations for this calculation.

PREREQUISITES
  • Understanding of wave mechanics and transverse waves
  • Familiarity with the formula v = √(FL/mass)
  • Knowledge of material properties, specifically the density of steel
  • Basic algebra for manipulating equations
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  • Research the density of steel and its relevance in wave speed calculations
  • Learn about the impact of wire diameter on wave propagation
  • Explore tension forces in different materials and their effects on wave speed
  • Review additional examples of wave speed calculations in various contexts
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Students in physics, particularly those studying wave mechanics, as well as educators and anyone involved in teaching or learning about the properties of materials and wave propagation in solids.

coffeem
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Homework Statement


A 2kg mass is suspended from a stell wire with a diameter 1mm and a length 0.75m. Caclulate the speed of the transverse wave along the wire.


Homework Equations


v = root(FL/mass)

where F - force of tension, L - length of wire, mass is mass.


The Attempt at a Solution



When I calculate this using the equation in the book I get v = 2.7m/s.

However this fails to take into account the diameter (cross sectional area of the string). Is this correct?
 
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In the problem mass of the wire is not given.

density = mass/ volume. = m/πr^2L.

So m/L = ρπr^2 where ρ is the density of the steel wire.
 
rl.bhat said:
In the problem mass of the wire is not given.

density = mass/ volume. = m/πr^2L.

So m/L = ρπr^2 where ρ is the density of the steel wire.

Are ok. The only problem is that i am not given the density and it has asked me to calculate the velocity of the wave. Given that it is a first year uni question and is only worth one mark, do you think they are expecting me to neglect the mass of the string?
 
No, I very strongly doubt you can neglect the mass of the string.

Perhaps the density of steel and other materials is given somewhere in the chapter that this problem is from. In which case you would be expected to look up the density.
 
Redbelly98 said:
Perhaps the density of steel and other materials is given somewhere in the chapter that this problem is from. In which case you would be expected to look up the density.

Id agree - but this is from a past examination paper... and it is not given? Do you think I am expected to memorize the density of steel? I will email the lecturer to ask, however I have a suspicion that you are meant to take the wire to be massless. I know this is wrong, but will the mass of the wire make a major difference? thanks
 
coffeem said:

Homework Equations


v = root(FL/mass)

where F - force of tension, L - length of wire, mass is mass.
"mass" refers to the mass of the steel wire here. It cannot be zero.

The 2 kg mass is only to provide tension in the wire, it does not contribute to "mass" in the above formula.

Best to ask the instructor for clarification at this point. Memorizing the density of anything other than water seems rather pointless to me, but the instructor may have reasons for doing so.
 
Redbelly98 said:
"mass" refers to the mass of the steel wire here. It cannot be zero.

The 2 kg mass is only to provide tension in the wire, it does not contribute to "mass" in the above formula.

Best to ask the instructor for clarification at this point. Memorizing the density of anything other than water seems rather pointless to me, but the instructor may have reasons for doing so.


I see - I have email the lecturer and asked. Ill see what he comes up with... thanks
 

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