Speed of falling object via derivation/integration

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SUMMARY

The discussion focuses on deriving the speed of a falling object, specifically a stone dropped from an initial height h, resulting in the equation v=sqrt(2gh). Participants clarify that while integration and derivation can be used, applying kinematic equations or energy principles is more straightforward. The key equation used is vf² = vi² + 2gh, which simplifies to the final velocity formula under the assumption of no air resistance. The acceleration due to gravity is represented as g, leading to the integration of dv/dt = g.

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  • Understanding of basic kinematics
  • Familiarity with integration and differentiation
  • Knowledge of gravitational acceleration (g)
  • Concept of energy conservation in physics
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  • Study the derivation of kinematic equations in physics
  • Learn about the principles of energy conservation and its applications
  • Explore the effects of air resistance on falling objects
  • Investigate advanced integration techniques in calculus
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Students studying physics, educators teaching kinematics, and anyone interested in the mathematical modeling of falling objects.

warfreak131
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Homework Statement



A stone is dropped from rest at an initial height h above the surface of the earth. Show that the speed with which it strikes the ground is v=sqrt(2gh)

Homework Equations





The Attempt at a Solution



I'm just not sure where to get started. I fully understand how to integrate/derive. I am having trouble understanding what equations to start with.

EDIT: I assume that I have to derive/integrate somewhere. I understand how to get sqrt(2gh) just by re-arranging the equation vf2 = vi2+2gh
 
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Assuming no air resistance, then the resultant force acting on the mass m is ma=mg.

You can write 'a' as 'dv/dt' and integrate.

Though using kinematics/energy is much simpler.
 
rock.freak667 said:
Assuming no air resistance, then the resultant force acting on the mass m is ma=mg.

You can write 'a' as 'dv/dt' and integrate.

Though using kinematics/energy is much simpler.

that would give me dv/dt = g. if i integrate with respect to t, id get v=gt

edit: nevermind, i got it,thanks
 

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