- #1

axe34

- 38

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## Homework Statement

## Homework Equations

I am aware that this can be done via energy methods. However, I wish to do it via:

integral between t1 and t2 of Torques about point (say centre of the wheel) = change in angular momentum of the wheel.

## The Attempt at a Solution

The torque is mgR. t1 is zero.

I get that the block hits the floor at t = (square root of 2gh)/g

When I use the change in angular momentum equation, I get w (omega) final as (2.m. (square root of 2gh))/MR but this supposedly is not correct.

Any ideas??