Speed of Light: Can We Reach It?

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SUMMARY

The discussion centers on the impossibility of reaching the speed of light due to the requirement of infinite energy, as momentum approaches infinity for massive objects. It clarifies that light, having no rest mass, operates under different principles where its energy is proportional to its frequency, described by the equations E=ħω and p=ħω/c. The distinction between massive objects and light is emphasized, highlighting that the rules governing energy and momentum differ significantly.

PREREQUISITES
  • Understanding of basic physics concepts, particularly momentum and energy.
  • Familiarity with the principles of special relativity.
  • Knowledge of quantum mechanics, specifically the relationship between energy and frequency.
  • Basic mathematical skills to interpret equations like E=ħω and p=ħω/c.
NEXT STEPS
  • Research the implications of special relativity on massive objects and light.
  • Explore the concept of rest mass and its significance in physics.
  • Study quantum mechanics, focusing on the relationship between energy and frequency.
  • Investigate advanced topics in momentum and energy conservation in relativistic physics.
USEFUL FOR

Students of physics, educators, and anyone interested in the fundamental principles of light and relativity will benefit from this discussion.

agent_509
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From what I understand, we can never reach the speed of light because it would require infinite energy, because our momentum would be infinite. But if that is the case, wouldn't light have infinite momentum and therefore infinite energy? Or am I an idiot and 'the speed of light' is just a term that has nothing to do with light?
 
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Since light has no "intrinsic", or rest, mass, the same rules do not apply to its energy/momentum as do for massive objects such as electrons, protons, and humans.

The rules applying to light state that its energy is proportional to its frequency, and its momentum has a similar relationship, only with a factor of 1/c:
[tex]E=\hbar \omega[/tex]
[tex]p=\frac{ \hbar \omega}{c}[/tex]
 
okay, I understand now, thanks!
 

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