songoku
				
				
			 
			
	
	
	
		
	
	
			
		
		
			
			
				
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- Homework Statement
- Sound wave produced by a bat has a frequency of 222 kHz and wavelength of ##1.5 x 10^{-3}## m. A stationary bat sends out a sound signal and receives the same signal reflected from a moving moth at a frequency of 230.3 kHz. Calculate the magnitude of the velocity of the moth, assuming that the velocity is constant
- Relevant Equations
- Doppler Effect
I treat this question as two cases of Doppler effect.
(1) When the sound wave travels from bat to moth
Speed of sound = 222 x 1.5 = 333 m/s
Frequency received by moth:
$$f_1=\frac{333+v}{333}\times 222$$
(2) When the sound wave is reflected from moth back to bat
Frequency received by bat (moth as source and bat as observer):
$$f_2=\frac{333}{333-v}\times f_1$$
$$230.3=\frac{333}{333-v}\times \frac{333+v}{333}\times 222$$
Solving this equation, I get ##v=6.1## m/s but the answer key is 12 m/s
Where is my mistake?
Thanks
				
			(1) When the sound wave travels from bat to moth
Speed of sound = 222 x 1.5 = 333 m/s
Frequency received by moth:
$$f_1=\frac{333+v}{333}\times 222$$
(2) When the sound wave is reflected from moth back to bat
Frequency received by bat (moth as source and bat as observer):
$$f_2=\frac{333}{333-v}\times f_1$$
$$230.3=\frac{333}{333-v}\times \frac{333+v}{333}\times 222$$
Solving this equation, I get ##v=6.1## m/s but the answer key is 12 m/s
Where is my mistake?
Thanks
 
 
		 
 
		