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Speed of the molecules on the gas kinetics theory

  1. Jan 24, 2006 #1
    How we can face the speed of the molecules on the gas kinetics theory and the speed barrier of light ?

    because v=sqrt(3kT/m)

    were k is boltzman
    T = kelvin
    and m = mass of the element


    remember the huge T of the big bang
     
  2. jcsd
  3. Jan 25, 2006 #2

    mma

    User Avatar

    Equipartition means E = 3kT/m (for a monoatomic gas). This involves v=sqrt(3kT/m) only when E=1/2 mv2, i.e. only for small v values (nonrelativistic speeds). In special relativity E=(1/2)mv2/sqrt(1-v2/c2).
    However v has an upper limit, kinetic energy doesn't. So temperature can be arbitrarily huge.
     
    Last edited: Jan 25, 2006
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