Speed of the molecules on the gas kinetics theory

Click For Summary
SUMMARY

The discussion focuses on the relationship between molecular speed in gas kinetics and the speed of light, emphasizing the equation v=sqrt(3kT/m), where k represents Boltzmann's constant, T is temperature in Kelvin, and m is the mass of the gas element. It highlights that while molecular speed is limited by the speed of light, kinetic energy can increase indefinitely, particularly in high-temperature scenarios such as the Big Bang. The concept of equipartition is introduced, stating that for a monoatomic gas, E=3kT/m, which applies under nonrelativistic conditions.

PREREQUISITES
  • Understanding of Boltzmann's constant (k)
  • Knowledge of the ideal gas law and gas kinetics
  • Familiarity with concepts of temperature (T) in Kelvin
  • Basic principles of special relativity and kinetic energy
NEXT STEPS
  • Explore the implications of the equipartition theorem in thermodynamics
  • Study the effects of temperature on molecular speed in various gases
  • Investigate the relationship between kinetic energy and relativistic speeds
  • Learn about the implications of the Big Bang on gas kinetics and temperature
USEFUL FOR

Physicists, chemists, and students studying thermodynamics and gas kinetics, particularly those interested in the effects of temperature on molecular behavior and the implications of special relativity.

geoorge
Messages
11
Reaction score
0
How we can face the speed of the molecules on the gas kinetics theory and the speed barrier of light ?

because v=sqrt(3kT/m)

were k is Boltzmann
T = kelvin
and m = mass of the element


remember the huge T of the big bang
 
Physics news on Phys.org
geoorge said:
How we can face the speed of the molecules on the gas kinetics theory and the speed barrier of light ?
because v=sqrt(3kT/m)
were k is Boltzmann
T = kelvin
and m = mass of the element
remember the huge T of the big bang
Equipartition means E = 3kT/m (for a monoatomic gas). This involves v=sqrt(3kT/m) only when E=1/2 mv2, i.e. only for small v values (nonrelativistic speeds). In special relativity E=(1/2)mv2/sqrt(1-v2/c2).
However v has an upper limit, kinetic energy doesn't. So temperature can be arbitrarily huge.
 
Last edited:

Similar threads

  • · Replies 10 ·
Replies
10
Views
3K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
24
Views
3K
  • · Replies 11 ·
Replies
11
Views
3K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 18 ·
Replies
18
Views
3K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 3 ·
Replies
3
Views
4K
  • · Replies 4 ·
Replies
4
Views
8K