Speed of waves and time delay question

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SUMMARY

The time delay for a television signal sent via satellite is calculated using the formula time = distance/speed. In this case, the satellite orbits at an altitude of 36,000 km, resulting in a total distance of 42,000 km from the Earth's center. The correct calculation for the round trip of the signal is 42,000 km x 2, leading to a time delay of 0.28 seconds when using the speed of light at 3x10⁵ km/sec. It is essential to consider the correct orbital radius when performing these calculations.

PREREQUISITES
  • Understanding of basic physics concepts, specifically wave propagation.
  • Familiarity with satellite communication principles.
  • Knowledge of the speed of light in a vacuum (3x10⁵ km/sec).
  • Ability to perform basic mathematical calculations involving distance and speed.
NEXT STEPS
  • Research the physics of satellite communication and signal propagation.
  • Learn about the different types of satellite orbits and their characteristics.
  • Explore the impact of atmospheric conditions on satellite signal transmission.
  • Study advanced calculations for signal delay in various orbital scenarios.
USEFUL FOR

Students studying physics, telecommunications engineers, and anyone interested in understanding satellite communication delays and calculations.

kirsten_2009
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Homework Statement


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What is the time delay for a television signal that is sent via satellite? Communications satellites orbit above the equator in circles of radius 36,000 km (6 times larger than Earth’s radius!).

Not sure if my answer is correct...

Homework Equations



time=distance/speed

The Attempt at a Solution




Not sure how satellite signals work but I assume that they operate on the surface of the Earth and that the signal travels to the Earth’s surface and back to the satellite…so the actual distance would be 36,000 km – 6,000 km (the distance from the center of the Earth to the surface) = 30,000 km x 2 (round trip) = 60,000 km.

time = distance / speed = 60,000 km / 3x10⁵ km/sec = 0.2 sec

 
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Your method is sound, but I'd double-check the orbit. 36,000 km is usually quoted as the orbit altitude, making 42,000 km radius from the Earth's center.
 

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