Sphere and electric field of infinite plate

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Homework Help Overview

The discussion revolves around a problem involving a charged sphere and an infinite conducting plate, focusing on the forces acting on the sphere to determine a position where the net forces are balanced, classifying it as a statics problem.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants explore the balance of forces on the sphere, questioning the inclusion of the sphere's repulsive force on the plate. There are discussions about Newton's third law and whether the plate is assumed to be fixed. Some participants inquire about the forces acting on the plate and the role of tension in the string.

Discussion Status

The discussion is active with participants raising questions about assumptions, interpretations of forces, and the nature of the problem. Some guidance has been offered regarding the balance of forces, but multiple interpretations are still being explored.

Contextual Notes

There are mentions of missing information regarding units for charge and charge density, as well as clarifications needed on the distribution of charge on the conducting plate.

annamal
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Homework Statement
Shown below is a small sphere of mass 0.25 g that carries a charge of ##9*10^{-10}##. The sphere is attached to one end of a very thin silk string 5.0 cm long. The other end of the string is attached to a large vertical conducting plate that has a charge density of ##30*10^{-6}##. What is the angle that the string makes with the vertical?
Relevant Equations
##\vec E = \frac{\sigma}{2\epsilon}##
The solution says that the tension in the string in the negative x direction is balanced by the force of the plate on the ball (red). Why is the repulsive force of the ball on the plate (in blue) not included in this calculation?

Screen Shot 2022-04-21 at 9.43.33 PM.png
 
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The problem requires us to find a position of the ball where the net sum of forces on it from plate, gravity and string is zero, so that the ball remains stationary. We call this a problem in 'statics', as opposed to a problem in 'kinetics' or 'dynamics' that involves motion.
To solve the problem we need only consider forces exerted on the ball, not forces that the ball exerts on other things.
 
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andrewkirk said:
The problem requires us to find a position of the ball where the net sum of forces on it from plate, gravity and string is zero, so that the ball remains stationary. We call this a problem in 'statics', as opposed to a problem in 'kinetics' or 'dynamics' that involves motion.
To solve the problem we need only consider forces exerted on the ball, not forces that the ball exerts on other things.
Would the force the ball exerts on the plate equal the force the plate exerts on the ball: ##q* \frac{\sigma}{2\epsilon}##?
 
annamal said:
Would the force the ball exerts on the plate equal the force the plate exerts on the ball: ##q* \frac{\sigma}{2\epsilon}##?
What did Newton say?
 
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haruspex said:
What did Newton say?
Equal and opposite, so I am guessing yes. So on the system of just the plate and the ball, there should be no net force since the electrical forces are equal and opposite?
 
annamal said:
Equal and opposite, so I am guessing yes. So on the system of just the plate and the ball, there should be no net force since the electrical forces are equal and opposite?
Yes.
 
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Is this problem assuming the conducting plate is fixed? Because if it isn't, wouldn't it fly to the left due to the force from the ball?
 
annamal said:
Is this problem assuming the conducting plate is fixed? Because if it isn't, wouldn't it fly to the left due to the force from the ball?
Yes. For me at least this is self implied, it is like doing a mechanics problem that involves (normal) forces from the ground and asking if the ground is fixed.
 
annamal said:
Is this problem assuming the conducting plate is fixed? Because if it isn't, wouldn't it fly to the left due to the force from the ball?
No, because just as the horizontal forces balance on the ball they also balance on the plate. But of course some torque must stop the plate/ball system falling over.
 
  • #10
haruspex said:
No, because just as the horizontal forces balance on the ball they also balance on the plate. But of course some torque must stop the plate/ball system falling over.
What are the horizontal forces that balance the plate? There is the force the ball exerts on the plate. There is no mention of a force countering that.
 
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  • #11
annamal said:
What are the horizontal forces that balance the plate? There is the force the ball exerts on the plate. There is no mention of a force countering that.
I think it must be a component of the force from the string to the plate.
 
  • #12
Delta2 said:
I think it must be a component of the force from the string to the plate.
I thought that only holds the ball in place.
 
  • #13
annamal said:
I thought that only holds the ball in place.
The string is under tension, so it pulls on whatever it is attached to at its two ends equally.
 
  • #14
To @annamal : Could you provide units for the charge on the sphere and the charge density?

I also have a question of interpretation. We have here a conducting plate "that has a charge density of ##30*10^-6##. Missing units notwithstanding, when the charged sphere is not in position, the charges can be assumed to be equally distributed on the left and right surfaces as shown in the figure. Is the number given the surface charge density on one of the surfaces or on each of the surfaces?
 
  • #15
kuruman said:
To @annamal : Could you provide units for the charge on the sphere and the charge density?

I also have a question of interpretation. We have here a conducting plate "that has a charge density of ##30*10^-6##. Missing units notwithstanding, when the charged sphere is not in position, the charges can be assumed to be equally distributed on the left and right surfaces as shown in the figure. Is the number given the surface charge density on one of the surfaces or on each of the surfaces?
They are SI units so ##C/m^2##...although the units are irrelevant to my actual question
 

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