What Is the Density of a Sphere Submerged in Water?

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To find the density of a sphere submerged in water and tethered to the bottom, the tension in the string is given as one-third the weight of the sphere. The net force equation is established as Fnet = 0 = Fb - T - mg, where T represents the tension, Fb is the buoyant force, and mg is the weight of the sphere. The relationship between tension, buoyant force, and the densities of the sphere and water is explored, leading to the equation T = (density of water - density of sphere) x (Volume of sphere) x g. By substituting the known value of T and rearranging the equations, the density of the sphere can be solved. Understanding these relationships is crucial for determining the sphere's density accurately.
05holtel
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Homework Statement



A sphere completely submerged in water is tethered to the bottom with a string.?
The tension in the string is one-third the weight of the sphere. What is the density of the sphere?

Homework Equations





The Attempt at a Solution



Fnet = 0 = Fb-T- mg

T=(Density of water x Volume of water x gravity) - (density of sphere x Volume of sphere x gravity)

T= (denisty of water - density of sphere) (Volume of object)(Gravity)

where volume of water = volume of sphere is completely submeged object

Not sure what to do now

Please help
 
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05holtel said:

The Attempt at a Solution



Fnet = 0 = Fb-T- mg
You are told what T is, so substitute what T is into that equation.

What's the buoyant force equal?

Hint: You want to rearrange the equation to solve for density, which is m/V.
 
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