Sphere Under Gravity Problem (Isaac Physics)

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The problem involves a small sphere attached to a string, moving in a vertical circle under gravity, with tension at the lowest point being three times that at the highest point. Initial assumptions of constant velocity were incorrect, as the sphere's speed varies at different points in the circle. Energy conservation principles were applied, comparing the energy at the top and bottom of the circle, while also analyzing forces using Newton's second law. The discussion emphasizes the need to differentiate velocities at the top and bottom and to resolve forces accurately to derive the necessary equations. A combination of energy and force analysis is essential to find the solution.
bobbricks
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I'm stuck on this problem:
A small sphere is attached to a fixed point by a string of length =30cm , and whirls round in a vertical circle under the action of gravity at such speed that the tension in the string when the sphere is at its lowest point is three times the tension when the sphere is at its highest point.
From: https://isaacphysics.org/questions/sphere_under_gravity

I initially thought it would be constant velocity but that produces the wrong answer and after looking at the hints, I found the velocity at the top is different to the velocity at the bottom.

I've tried using ideas of energy where the Energy at the top=mg0.6+0.5mv2 and Energy at the bottom= 0.5mv2

Also, resolving forces: At the top F=T+mg where F is the centripetal force. At the bottom F=3T-mg.

I've also tried working out the minimum velocity required using a=v2/r where a=9.81 and r=0.3m. I've tried to use Work=forcexdisplacement so F=W/d and d=0.6 and W=energy at the top or W= energy at the bottom, to produce 2 separate equations. Still stuck.
 
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You'll need both energy analysis (conservation) and force analysis (Newton's 2nd law) to solve this.

bobbricks said:
I've tried using ideas of energy where the Energy at the top=mg0.6+0.5mv2 and Energy at the bottom= 0.5mv2
Give the velocities at top and bottom different symbols and apply conservation of energy.

bobbricks said:
Also, resolving forces: At the top F=T+mg where F is the centripetal force. At the bottom F=3T-mg.
Good. Apply Newton's 2nd law to top and bottom positions.

That will give you the equations you need to solve for the speeds.
 
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