Sphere Under Gravity Problem (Isaac Physics)

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SUMMARY

The Sphere Under Gravity problem involves a small sphere attached to a fixed point by a 30 cm string, moving in a vertical circle under gravity. The tension in the string at the lowest point is three times that at the highest point. To solve this problem, one must apply both energy conservation principles and Newton's second law, resulting in two key equations that relate the velocities at the top and bottom of the circle. The correct approach requires differentiating the velocities at these points and resolving forces accordingly.

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  • Familiarity with centripetal force concepts
  • Ability to manipulate algebraic equations
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This discussion is beneficial for physics students, educators, and anyone interested in solving mechanics problems involving circular motion and gravitational forces.

bobbricks
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I'm stuck on this problem:
A small sphere is attached to a fixed point by a string of length =30cm , and whirls round in a vertical circle under the action of gravity at such speed that the tension in the string when the sphere is at its lowest point is three times the tension when the sphere is at its highest point.
From: https://isaacphysics.org/questions/sphere_under_gravity

I initially thought it would be constant velocity but that produces the wrong answer and after looking at the hints, I found the velocity at the top is different to the velocity at the bottom.

I've tried using ideas of energy where the Energy at the top=mg0.6+0.5mv2 and Energy at the bottom= 0.5mv2

Also, resolving forces: At the top F=T+mg where F is the centripetal force. At the bottom F=3T-mg.

I've also tried working out the minimum velocity required using a=v2/r where a=9.81 and r=0.3m. I've tried to use Work=forcexdisplacement so F=W/d and d=0.6 and W=energy at the top or W= energy at the bottom, to produce 2 separate equations. Still stuck.
 
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You'll need both energy analysis (conservation) and force analysis (Newton's 2nd law) to solve this.

bobbricks said:
I've tried using ideas of energy where the Energy at the top=mg0.6+0.5mv2 and Energy at the bottom= 0.5mv2
Give the velocities at top and bottom different symbols and apply conservation of energy.

bobbricks said:
Also, resolving forces: At the top F=T+mg where F is the centripetal force. At the bottom F=3T-mg.
Good. Apply Newton's 2nd law to top and bottom positions.

That will give you the equations you need to solve for the speeds.
 

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