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Sphere's Electric Potential...HELP!
A 2.04-mm-diameter ball bearing has 8.710×10^9 excess electrons. What is the ball bearing�s potential?
V = (1/4*pi*Eo) * (Q/r)
Eo = 8.85 x 10^-12
Q = 1.6x10^-19 * 8.71x10^9
r = 0.00204/2
V = 12308.78 V
Can someone tell me what I am doing wrong?
Homework Statement
A 2.04-mm-diameter ball bearing has 8.710×10^9 excess electrons. What is the ball bearing�s potential?
Homework Equations
The Attempt at a Solution
V = (1/4*pi*Eo) * (Q/r)
Eo = 8.85 x 10^-12
Q = 1.6x10^-19 * 8.71x10^9
r = 0.00204/2
V = 12308.78 V
Can someone tell me what I am doing wrong?