Sphere's Electric Potential HELP

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Homework Help Overview

The discussion revolves around calculating the electric potential of a sphere, specifically a ball bearing with a given diameter and excess electrons. The problem involves applying concepts from electrostatics.

Discussion Character

  • Exploratory, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to use the formula for electric potential, incorporating the charge and radius of the sphere. A participant questions the method of calculating the charge by suggesting that multiplying by epsilon-zero may not be appropriate.

Discussion Status

The discussion includes an initial attempt at a solution, followed by a question about the approach taken. The original poster indicates they have resolved their issue, but the specifics of that resolution are not detailed. There is no explicit consensus on the method used.

Contextual Notes

There is a lack of clarity regarding the application of constants and the calculation of charge, which may impact the understanding of the problem. The original poster's resolution is not elaborated upon, leaving some ambiguity in the discussion.

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Sphere's Electric Potential...HELP!

Homework Statement


A 2.04-mm-diameter ball bearing has 8.710×10^9 excess electrons. What is the ball bearing�s potential?


Homework Equations





The Attempt at a Solution


V = (1/4*pi*Eo) * (Q/r)
Eo = 8.85 x 10^-12
Q = 1.6x10^-19 * 8.71x10^9
r = 0.00204/2
V = 12308.78 V

Can someone tell me what I am doing wrong?
 
Physics news on Phys.org
Why are you multiplying your excess charge by Epsilon-not to get Q?
 
nevermind I just got it...thanks though!
 
Great!
 

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