Spherical coordinates vector question

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SUMMARY

The discussion centers on the application of spherical coordinates in vector calculus, specifically addressing the divergence of a radial vector field. The correct formula for divergence in spherical coordinates is established as \(\frac{1}{r^2} \frac{\partial}{\partial r} (r^2 F)\), where \(F\) represents the magnitude of the vector function. The user initially misapplied the divergence operation, leading to confusion regarding the expression \(\nabla \cdot \underline{r} = 3\). The correct interpretation involves recognizing that for a purely radial function, \(F = r\).

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Students of physics and mathematics, particularly those studying vector calculus and spherical coordinates, will benefit from this discussion. It is also relevant for educators seeking to clarify concepts related to divergence in radial vector fields.

renlok
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I've no idea where to put this question but here it is I am trying to work through the examples our lecture has given in class and I wasn't getting them at all
the first thing that confused me was \nabla . \underline{r} = 3 I tried this myself with \nabla . \underline{r} = \frac{1}{r^2}\frac{\delta{r^2}}{\delta{r}} = \frac{2}{r} (working in spherical coords)
but if you use \textbf{e_r} = \frac{\textbf{r}}{r} it works but I have no idea where this comes from could someone at least point me in the right direction that would be really helpful thanks

 
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You should try to use the template. But oh well.

You've had a go at using spherical coordinates - yep that's one way to do it. But I think you've done it wrong. When the function is purely radial (as it is in your case), the divergence is equal to:

\frac{1}{r^2} \frac{\partial}{\partial r} (r^2 F)
(where F is the magnitude of the vector function in question). For your problem, F=r.
 

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