Spherically symmetric charge density

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SUMMARY

The discussion focuses on calculating the electric field E(r) and potential V(r) for a spherically symmetric charge density defined as p(r) = Cr for r ≤ a and p(r) = 0 for r > a. The electric field is derived using Gauss's Law, leading to the expression E(r) = Cπr^4 for r ≤ a. The continuity of E(r) and V(r) at r = a is questioned, particularly when an additional surface charge density σ is introduced at r = a. The participants emphasize the importance of leveraging local laws over integral laws in solving these electrostatic problems.

PREREQUISITES
  • Understanding of Gauss's Law in electrostatics
  • Familiarity with spherical symmetry in charge distributions
  • Basic knowledge of electric fields and potentials
  • Ability to perform integration in the context of physics problems
NEXT STEPS
  • Study the application of Gauss's Law for different charge distributions
  • Learn about the continuity conditions for electric fields and potentials
  • Explore the concept of surface charge density and its effects on electric fields
  • Investigate the direct solutions for electrostatic potentials in various charge configurations
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Students and educators in physics, particularly those focusing on electrostatics, as well as professionals working with electric field calculations and charge distributions.

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Homework Statement



Imagine a spherically symmetric charge density p(r)=Cr for r<=a, p(r)=0 for r>a.
a) Find the electric field E(r) and potential V(r). Are they continuous at r=a?
b) Suppose additional charge is placed uniformly on the surface at r=a with surface density sigma. Find E(r) and V(r). Are they continuous at r=a? Explain.

Homework Equations



gausses law

The Attempt at a Solution


[/B]
So for part a to find the electric field I think I integrate from 0 to r with the integrand being Cr4pi r^2 dr and then add the integral from 0 to a of 0*4 pi r ^2 dr. And i get Cpir^4 ? is this correct? How can I get the potential and to know if they are continuous? I am guessing they are not??

Also I am lost on part b - please help.
 
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Hm, I'd rather use the local laws, which are almost always so much more powerful than the integral laws.

Here, however, you can also use the integral law due to the very symmetric situation. Write down the relevant equation. You got already one side of this equation correct. Now you have to think about the other side of the equation, i.e., to check, which quantities you need and how you can get them from this equation, taking into account the spherical symmetry of the problem. Finally you can think about the potential.

Of course, there's also a direct solution for the electrostatic potential for a given static charge distribution, but the question sounds as if you should not ;-)).
 

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