Spivak's Calculus: Chap 1: Problem 3i - Simple Proof

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Homework Help Overview

The problem involves proving the equation \(\frac{a}{b} = \frac{ac}{bc}\) under the condition that \(b\) and \(c\) are not equal to zero. The context is rooted in basic properties of numbers as discussed in Spivak's calculus text.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to demonstrate the proof using the definition of \(c/c\) and properties of fractions. Some participants question the completeness of the proof and whether additional justification is needed for each step. Others suggest referring to specific properties listed in Spivak's book to support the proof.

Discussion Status

Participants are actively engaging with the problem, discussing the need for rigor in the proof and the importance of documenting each step with appropriate properties. There is an acknowledgment of the original poster's understanding, but also a recognition that further clarification and justification may enhance the proof.

Contextual Notes

There is an emphasis on the assumptions that \(b\) and \(c\) are not zero, and the discussion includes references to specific properties from Spivak's text that should be utilized in the proof.

Saladsamurai
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Homework Statement



Prove that

[tex]\frac ab = \frac{ac}{bc}[/tex]

Homework Equations



Basic properties of numbers



The Attempt at a Solution



I really don't understand what is left to show here? By definition c/c means c*c-1 = 1. So is that is? That is:

[tex] \begin{array}{l}<br /> \frac ab &= \frac ab \cdot c\cdot c^{-1} \\<br /> &= \frac ab \frac cc \\<br /> &= \frac {ac}{bc}<br /> \end{array}[/tex]


I dunno. Is that it?
 
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Please state the entire problem. Are a, b, and c numbers or from some abstract algebraic structure? Is it assumed that c is not 0?
 
The whole problem is:
Prove the following:

[itex]\frac{a}{b}=\frac{ac}{bc}[/itex] if b and c do not equal 0.


What spivak wants you to do is flip back to about page 9 where he lists his P1-P12 properties and use those to document each step.
 
Hello :smile:

HallsofIvy said:
Please state the entire problem. Are a, b, and c numbers or from some abstract algebraic structure? Is it assumed that c is not 0?

As QC has noted, yes c and b not 0.
QuarkCharmer said:
The whole problem is:
Prove the following:

[itex]\frac{a}{b}=\frac{ac}{bc}[/itex] if b and c do not equal 0.What spivak wants you to do is flip back to about page 9 where he lists his P1-P12 properties and use those to document each step.

Hi QC So that's what I thought. Does my proof lack anything? I am not sure what is left to document, if anything. I guess to be complete I should show that [itex]\frac ab \frac cc = \frac{ab}{cc}[/itex] by writing them as [itex](ab^{-1})(cc^{-1})[/itex] and using the associate property to rearrange them.

Just trying to get a feel for how these proofs should be written (in a formal sense).

Thank you. :smile:
 
The first chapter of Spivak's book really emphasizes rigor. If you really wanted to formalize it, you'd have to add more statements justifying your proof. For instance, there's no property that says you can multiply any number by [itex]c \cdot c^{-1}[/itex]; there is one (P6) that says you can multiply any number by the identity, symbolized by [itex]1[/itex], and there's another one (P7) which says that [itex]c \cdot c^{-1} = 1[/itex].

For these beginning exercises, it's probably worth it to go a little overboard with the rigor. Line by line proof, with properties or theorems to the right justifying each step. I think Spivak's intention is to really build a solid base, and to do that you have to really forget everything you know, which is near impossible. That being said, you clearly have the right idea.
 

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