Spring Compression from 8.0kg Mass Sliding 7.00m Down 51deg Incline

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SUMMARY

The discussion centers on a physics problem involving an 8.0 kg block sliding down a frictionless incline of 51 degrees and compressing a spring after traveling 7.00 meters. The force exerted by the block upon contact with the spring is calculated to be 60.928 N using the formula 9.8cos(90-51) multiplied by the mass. The kinetic energy of the block at the moment of contact is also a key factor in determining the spring's compression, although the spring constant is not provided in the problem statement, which is essential for calculating the exact compression distance.

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block of mass 8.0 kg slides from rest down a frictionless 51degree incline and is stopped by a strong spring with The block slides 7.00 m from the point of release to the point where it comes to rest against the spring. When the block comes to rest, how far has the spring been compressed?

First i determine the force of the block against the spring when it comes in contact with it
9.8cos(90-51)=7.616x8.0=60.928N
and i determine kinetic energy of the block when it comes in contact with the spring.
Then how do i determine how much the force that the block exerts on the spring and how much the kinetic energy that is trasferred to the spring from the block cause the spring to be compressed?
 
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Is there a spring constant given with the problem?
 

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