Spring Constant & Potential Energy

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SUMMARY

The discussion centers on calculating the potential energy of a fully compressed plastic spring and determining its spring constant using Hooke's Law. The measured variables include a spring height of 0.115 meters when uncompressed and 0.0450 meters when compressed, with a mass of 0.0148 kg. The calculated potential energy is 0.00508 J, and the spring constant is determined to be 2.074 N/m. The results are confirmed as accurate, indicating that the spring may be weak.

PREREQUISITES
  • Understanding of Hooke's Law and its application in spring mechanics.
  • Basic knowledge of potential energy calculations in physics.
  • Familiarity with units of measurement such as meters and Newtons.
  • Ability to perform calculations involving mass and gravitational acceleration (9.81 m/s²).
NEXT STEPS
  • Explore advanced applications of Hooke's Law in different spring systems.
  • Learn about energy conservation principles in mechanical systems.
  • Investigate the effects of material properties on spring performance.
  • Study the relationship between spring constant and oscillation frequency in harmonic motion.
USEFUL FOR

Students in physics, particularly those studying mechanics, as well as educators and anyone involved in experimental physics or engineering applications related to springs and energy calculations.

Bonana
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Homework Statement


Problem - Find the following:
a. Potential energy in a fully compressed plastic spring.
b. Spring constant

This was a lab and we're supposed to do it at home, here are the variables I have measured:
spring height when not compressed: 0.115 metres.
spring height when completely compressed: 0.0450 metres
mass of spring: 0.0148kg


Homework Equations


Hookes Law:
Ep = 1/2kx^2
Fs = mg

The Attempt at a Solution


The answers we got seemed extremely low.
A)1/2(2/074N/m)(0.07m)^2 = 0.00508J
B)(0.0148kg)(9.81m/s^2)/0.07m = 2.074N/m


Any help would be great.
 
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Dear Bonana,
could you tell a bit about the setup of the experiment? How did the spring get compressed: by an external force or by its own weight?
 
Bonana said:

Homework Statement


Problem - Find the following:
a. Potential energy in a fully compressed plastic spring.
b. Spring constant

This was a lab and we're supposed to do it at home, here are the variables I have measured:
spring height when not compressed: 0.115 metres.
spring height when completely compressed: 0.0450 metres
mass of spring: 0.0148kg


Homework Equations


Hookes Law:
Ep = 1/2kx^2
Fs = mg

The Attempt at a Solution


The answers we got seemed extremely low.
A)1/2(2/074N/m)(0.07m)^2 = 0.00508J
B)(0.0148kg)(9.81m/s^2)/0.07m = 2.074N/m


Any help would be great.

If these are the measured data, the results are correct. It can be a weak spring.

ehild
 

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