Spring Constants and compression

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The discussion revolves around calculating the spring constant and understanding forces acting on a mass hanging from a spring scale. When the mass is not in contact with the spring, the scale reads 49 N due to the weight of the 5.0 kg mass. To find the spring constant, the scale reading of 20 N when the spring is compressed by 2.0 cm must account for the weight of the mass, leading to a corrected calculation. The correct approach involves recognizing that the vertical spring must exert enough force to support the weight, resulting in a need to factor in the 49 N when determining the spring constant. For the scale to read 0 N, the spring must be compressed by approximately 3.38 cm, considering the weight of the mass.
anotherperson
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Homework Statement


A 5.0kg mass is hanging from a spring scale and is slowly lowered onto a vertical spring. The scale reads in Newtons.

a) what does the scale read when the mass is not in contact with the spring?
b)the scale reads 20N when the lower spring is compressed by 2.0cm. show that the value of the spring constant of the lower spring is 1450 N/m
c) by how much must the lower spring be compressed for the scaled to read 0.0N


Homework Equations


Fnet=ma
Fsp=-kdeltax


The Attempt at a Solution



a)F=5X9.8
=49N

b) 20=-kX2.0

but i get the wrong answer??

c) is i do
0=1450x
then x=0
?
 
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Your answer to a) looks good.

Your answer to be would be correct if the spring were weightless, but you have calculated that it pulls down with a force of 49 N. How can you take that into account in b)?

For c), you must again allow for the 49 N that the scale reads when no weight is on it. I think you see you could make the scale read less if you push up of the spring. How hard would you ahve to push for it to read 0 Newtons?
 
for part b, I am still unsure how you factor in the 49N, i have a feeling you would add it but into what rule would you use these numbers, the rule i have used above?

so for part c you do 49N divided by the spring constant of 1450 and you get an answer of 3.38 cm which matches my answers, thanks!
 
anotherperson said:
b) 20=-kX2.0

but i get the wrong answer??
20 N is the reading on the spring scale, not the force compressing the vertical spring. If the spring scale reads 20 N, how much force must the vertical spring exert on the mass in order to support its weight?

(Hint: There are three forces acting on the mass. What are they? What must the net force be?)
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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