Spring-Loaded Gun-spring constant

  • Thread starter Thread starter gaimon
  • Start date Start date
  • Tags Tags
    Constant
Click For Summary
SUMMARY

The discussion focuses on calculating the spring constant for a spring-loaded gun that launches a 25.4g projectile to a maximum height of 24.0m after compressing the spring by 0.147m. The initial calculation using Hooke's law (k=mg/x) yielded an incorrect spring constant of 1693.3 N/m due to the misapplication of mass in grams instead of kilograms. The correct approach involves considering the gravitational potential energy at the maximum height and the elastic potential energy stored in the spring, emphasizing the importance of the projectile's height in determining the spring constant.

PREREQUISITES
  • Understanding of Hooke's Law and spring mechanics
  • Knowledge of gravitational potential energy calculations
  • Familiarity with unit conversions, specifically mass from grams to kilograms
  • Basic principles of energy conservation in physics
NEXT STEPS
  • Review the derivation of Hooke's Law and its applications in mechanics
  • Study the relationship between gravitational potential energy and elastic potential energy
  • Learn about unit conversions, particularly converting grams to kilograms for physics calculations
  • Explore the concept of energy conservation in projectile motion
USEFUL FOR

Physics students, engineers, and anyone interested in understanding the mechanics of spring-loaded devices and energy conservation principles in projectile motion.

gaimon
Messages
9
Reaction score
0
Okay, so having a bit of trouble with this problem. There is a spring loaded gun pointing vertically in the air. If the spring in the gun is compressed a distance of 0.147 m, the gun can launch a 25.4g projectile from rest to a maximum height of 24.0 m above the starting point of the projectile. Neglecting all resistive forces, determine the spring constant.

What I've done so far is first assume the distance the projectile travels is irrelevant.
Then using Hooke's law: k=mg/x so k=25.4(9.8)/0.147.
I keep coming up with the answer 1693.3 N/m but am told that that is not correct.

What am I doing wrong?
 
Physics news on Phys.org
Newton's are kilograms*m/s^2; you're using a mass measured in grams.

However, you're assuming that the weight of the mass is compressing the spring that distance. There's a mysterious hand that pushed the mass down until some mechanism clicked and held it into place. Otherwise, when you pull the trigger, it's not going to go anywhere.

Do you have a formula for the elastic energy of the spring? The maximum height of the projectile is very important in this problem.
 

Similar threads

Replies
29
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 14 ·
Replies
14
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 58 ·
2
Replies
58
Views
3K
  • · Replies 10 ·
Replies
10
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
1
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K