Spring mass system with applied force kinetic energy

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SUMMARY

The discussion focuses on modeling a spring mass system with an applied force using Lagrangian mechanics. The user seeks clarification on calculating kinetic energy, specifically using the formula KE = 1/2 mv² and the work-energy principle expressed as ΔKE + ΔPE = W. The conversation highlights the importance of distinguishing between impulse and work, with the user planning to extend their calculations to double spring systems with applied forces.

PREREQUISITES
  • Lagrangian mechanics
  • Kinetic energy calculations
  • Work-energy principle
  • Impulse vs. work differentiation
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  • Study the application of Lagrangian mechanics in complex systems
  • Explore the work-energy theorem in detail
  • Investigate double spring systems and their dynamics
  • Learn about impulse and its relation to work in physics
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Physics students, mechanical engineers, and anyone interested in advanced dynamics and energy calculations in spring mass systems.

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I'm trying to work out a model for a spring mass system with a force acting at the centre of mass of the mass using Lagrangian mechanics. I can't work out the kinetic energy. I know the kinetic energy \text{KE}=\dfrac{1}{2}mv^2. I also have W=\int_a^b F \, dt.
Should I use \Delta \text{KE} + \Delta \text{PE} =W

Some help will be appreciated.

P.S. I'm using Lagrangian mechanics because later I'm planning some calculations on double spring systems with applied force.
 
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W = \int \vec{F} \cdot \vec{dx}

The expression you had was for Impulse not Work
 

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