Spring Problem Solution: Calculating Maximum Movement with Masses Attached

[xcvxcvvc]

Homework Statement

A spring is hung from the ceiling. A pan of mass 100.0 g is attached to the end, which causes it to stretch 5.00 cm. Find the maximum distance the pan moves downward when a lump of clay of mass 120.0 g is dropped from a height of 40.0 cm onto the pan.

Homework Equations

K * distance = force of spring
integral(kx) = work
momentum p1 + p2 = p1' + p2'
potential energy = g * h * m

The Attempt at a Solution

.1 * 9.8 = k * .05, k = 19.6N/s
integral from .05 to x of 19.6x dx = .120 * .4 * 9.8 SO

9.8 * x^2 - 9.8(.05) = .4704
x = .313 m
.313 - .05 = .263 meters maximum movement downward

the answer is 0.233 m

 

[4.19mile]

Correct.

 

[xcvxcvvc]

no, it's off by .03 meters. I'm not sure why.

my answer is .263 and the real answer is .233

 

[4.19mile]

Fine, wrong.

 

[xcvxcvvc]

Fine, wrong.

lol thanks for the help

 

[4.19mile]

No problem.

 

[xcvxcvvc]

LOL that was the right answer, i just used wrong math