Springs in series and parallel : Problem for U

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The discussion revolves around a question regarding the compression of two identical springs when subjected to a force in series versus parallel. The original answer given was 2.5 cm for the parallel configuration, which was confirmed as correct by other participants. The logic explained includes that in series, each spring compresses by 5 cm under a 5 kg force, while in parallel, the force is divided, resulting in 2.5 kg per spring, leading to a 2.5 cm compression. There was a clarification needed regarding the units of force, as one participant mistakenly referred to force in Newtons instead of kilograms. The conversation emphasizes the importance of using the correct spring constants and units in such calculations.
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I came across an objective question on the topic 'Springs in series and parallel' .. Have i asnwered it correctly?

Q. A Force of 5Kg compresses 2 springs in series by 10 cm. What will be the compression when the same force acts on the same 2 springs but when the springs are in parallel?

Choices >>
1) 5 cm
2) 10 cm
3) 2.5 cm
4) 20 cm

MY ANSWER >> 2.5 cm

Please correct me if I am wrong..
 
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You are correct !
though it should have been mentioned that the springs are identical but as nothing is mentioned we can take them to be identical
 
Thanks buddy...

Oh yes, U r spot on.. I forgot to mention that the springs are identical..

The logic I followed was >>

In series,
* The compression is 10 cm
* This means each spring compresses by 5cm
* Since the springs are in series, both the springs experience the full 5 kg
force
* So, each spring compresses 1 cm for 1 kg (Spring constant=1)

In parallel,
* Now, the force is divided between the 2 springs
* So, force acting on each spring is 2.5 N
* So, in this case, the spring compresses to 2.5xSpring constant(1) = 2.5 cm

Hope I am right with my logic too.. Sorry, I should have mentioned this earlier:biggrin:
 
most welcome

well...your logic seems correct but some problem in units.

u say spring constant is 1??
if its 1 it must be 1 cm/kg wt but in si it will be not be so

but later you say the force on each spring is 2.5 N it can't be its 2.5kg wt

otherwise your soln is correct

n btw ...
if you are preparing for some objective type examinatiom
then you can use
for series
1/k=1/k1+1/k2
and parallel
k=k1+k2
where k is equivalent spring constant
 
Thanx chap..:approve:

(Ooops, the 2nd force that I mentioned is 2.5 KG (Not Newton) ... by mistake I wrote it as 2.5N)
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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