MHB Squaring Radical Within A Radical

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(-2sqrt{8 - 2{7}})^2

(-2sqrt{8 - 2{7}})(-2sqrt{8 - 2{7}})

4(8 - 2sqrt{7})

Correct?
 
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Yes.
 
greg1313 said:
Yes.

Can it be further simplified?
 
Originally you had "(-2sqrt{8 - 2{7}})^2". Where did the sqrt{7} come from? Did you intend to write "(-2sqrt{8 - 2sqrt{7}})^2"?
 
HallsofIvy said:
Originally you had "(-2sqrt{8 - 2{7}})^2". Where did the sqrt{7} come from? Did you intend to write "(-2sqrt{8 - 2sqrt{7}})^2"?

Yes, I intend to write (-2sqrt{8 - 2sqrt{7}})^2.
 
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