Squeezing f(x) Between g(x) and h(x): Cos, Sin, & Tan

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SUMMARY

The discussion focuses on applying the Squeeze Theorem to the function f(x) = x4 cos(2/x6). Participants seek to determine the bounding functions g(x) and h(x) that satisfy g(x) ≤ f(x) ≤ h(x) as x approaches zero. The Squeeze Theorem states that if the limits of g(x) and h(x) converge to the same value L, then the limit of f(x) as x approaches c must also equal L. The key challenge is identifying appropriate g(x) and h(x) for this specific function.

PREREQUISITES
  • Understanding of the Squeeze Theorem in calculus
  • Familiarity with trigonometric functions, specifically cosine
  • Knowledge of limits and their properties
  • Basic algebraic manipulation skills
NEXT STEPS
  • Research the Squeeze Theorem and its applications in calculus
  • Study the behavior of the cosine function as its argument approaches infinity
  • Explore limit evaluation techniques for polynomial and trigonometric functions
  • Practice solving limit problems involving trigonometric functions and polynomial bounds
USEFUL FOR

Students and educators in calculus, mathematicians exploring limit concepts, and anyone seeking to deepen their understanding of the Squeeze Theorem and its applications in evaluating limits of complex functions.

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f(x)=x4 cos(2/x6)

g(x) <= f(x) <= h(x)

how to get g(x) and h(x) by using the squeeze theorem??

I know is something like this -1 <= x <= 1

But how do i implement it here, and especially to the cos, sin, and tan??
 
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solve the problem!
 
So in your question, x^4 . cos \frac{2}{x^6} what's the limit ie. as x approaches what? zero?

Then we can use the squeezing theorem; g(x) \leq f(x) \leq h(x)
Assuming that the limit of f(x) as x approaches c is L then;

lim_{x \rightarrow c} g(x) = lim_{x\rightarrowc} h(x) = L

Thus lim_{x \rightarrow c} f(x) = L
 
Last edited:
What exactly is the question? The "squeeze theorem" refers to limits but you are trying to find the limit of x4cos(2/x6) as x goes to what?


(And it is your responsibility to "solve the problem"!)
 

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