Standing Sound Waves: Wavelengths in 121 cm Tube - SOLVED

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SUMMARY

The discussion focuses on calculating the three longest wavelengths for standing sound waves in a 121 cm tube, specifically for two configurations: open at both ends and open at one end, closed at the other. For the open-open configuration, the wavelength is determined using the formula λ = 2L/m, where m represents the mode number (m = 1, 2, 3, 4...). For the open-closed configuration, the formula is λ = 4L/m, with m taking odd values (m = 1, 3, 5, 7...). The three longest wavelengths correspond to the three lowest modes in each case.

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  • Understanding of standing sound waves
  • Familiarity with wavelength equations for open and closed tubes
  • Basic knowledge of wave modes
  • Ability to perform calculations involving lengths and modes
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[SOLVED] Standing Sound Waves

What are the three longest wavelengths for standing sound waves in a 121 cm long tube that is (a) open at both ends and (b) open at one end, closed at the other?


the wavelength equation that i used for open-open was [tex]\lambda[/tex]= 2L/m; where m is the number of modes (m=1,2,3,4...)

and then for open-closed [tex]\lambda[/tex]= 4L/m; where m is the number of modes (m=1,3,5,7...)

so i have the length, but the one question that i have about this problem is could i start with the lowest number of modes, but if that is true then why ask for the three longest wavelength, so i am kind of lost if anyone could give me a clue on what to do

thanks in advance
 
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The three longest wavelengths correspond to the three lowest modes.
 
oh ok, that was exactly what i thought it was thanks
 

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