# Standing waves in tube closed tube

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1. Apr 29, 2015

### Arcthor

1. The problem statement, all variables and given/known data
A tone with frequency 2,00 * 10^3 Hz is held above a tube filled with water. The water level is increased and decreased.

When the water level is 5.7cm below the opening of the tube, the first sound maxima is heard.

When the water level is 39.3cm below the opening of the tube, the fifth sound maxima is heard.

Questions:
1. what is the wavelength?
2. What is the speed of sound in this specific experiment?

2. Relevant equations
v=wavelength*frequency

3. The attempt at a solution
My attempt is as follows:

(39.3 - 5.7) = delta distance, and there are four wavelengths between the first and the fifth maxima, therefore the answer should be:

(39.3-5.7) / 4 = 8.4

2. Apr 29, 2015

### BvU

When is there a sound resonance ? Your title says closed tube. Are both sides closed ?

3. Apr 29, 2015

### CWatters

That's not correct. Try drawing the 5 cases.

4. Apr 29, 2015

### Arcthor

Sorry, the water makes up the closed part. The opening is open.

5. Apr 29, 2015

### Arcthor

What am I missing?

6. Apr 29, 2015

### BvU

You have to look at the amplitudes of standing waves (fig 3).

7. Apr 29, 2015

### CWatters

+1 to that.

"the first sound maxima" is a reference to resonance not to wave peaks. See the link BvU posted.