State Space Form of Projectile EOM with Air Resistance

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SUMMARY

The discussion focuses on converting the equations of motion for a projectile with air resistance into state space form. The equations provided are m \ddot{q_1} = -k \dot{q_1} and m \ddot{q_2} = -k \dot{q_2} - mg, with the state defined as X = [q; \dot{q}]. The user clarifies that state space form is represented as a first-order vector ODE: \dot{X} = f(X), where f(X) is a vector function derived from the original equations. The user successfully resolves their confusion regarding the notation and the conversion process.

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  • Understanding of Newton's laws of motion
  • Familiarity with vector calculus
  • Knowledge of state space representation in control systems
  • Basic concepts of differential equations
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  • Study the derivation of state space representation for dynamic systems
  • Learn about first-order vector ordinary differential equations (ODEs)
  • Explore the application of air resistance in projectile motion analysis
  • Investigate numerical methods for solving state space equations
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I have equations of motion for a projectile with air resistance: where [tex]q = [x; y][/tex]

[tex]m \ddot{q_1} = -k \dot{q_1}[/tex]
[tex]m \ddot{q_2} = -k \dot{q_2} - mg[/tex]

I need to convert it into state space form, with the state [tex]X = [q; \dot{q}][/tex]. I'm told state-space form is a first order vector ODE: [tex]\dot{X} = [\dot{q}; \ddot{q}] = f(X)[/tex]

Now I'm confused. I can write my equations of motions in matrix form like: [tex]m\ddot{q} = -k \dot{q} - [0; mg][/tex]. Is writing this in state-space form like vectorizing it again? Also, is f(X) a matrix? It's hard for me to figure out the problem without understanding the notation...
 
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Nevermind, got it. Was a lot easier than I thought.
 

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